Hi Jon,
Try that, no pumping losses included:
Air requirement per mn, normally aspirated
(Cyl in litres + Head in litres) x number of cyl x rpm/2 (4 stroke) = AR
Then Boost ratio:
(atm pressure (14.7) + turbo boost)/turbo boost = BR
Then air requirement per mn, with turbo:
AR x BR= ART in litres
Then weight of air in ART = (ART/1000) x 1.2) = ARTW
Then Methanol bit:
ARTW / 6 (meth to air mix ratio) x .792 (specific meth gravity) = meth needed in litres per mn
Hum, thinks it's right!!!
Patrick