If we keep our total loss cooling system, of 60 litres (+engine cooling system cap.) is this the right formula to calculate whether we have enough volume?
Specific Heat Capacity (C_p) for water @ room temp is 4.1813 J/(g*K)
K is Kelvin
The equation is Q = m*C_p*delta_T, where Q=heat energy, m=mass of water in grams, C_p = 4.1813, and delta_T = change in temp in either K or degC.
for a safe margin of error lets say we are making 350Kw ( 470 hp) for 8mins. 60 litres, raising the temp by 65 degrees C.