Thank you all for the comments and PM's that is really good input and seems to make sense now.

Please let me know if I have got it wrong....

So if we work on 0.6g being the maximum traction available on salt, at 200 mph the minimum radius would need to be no less than 4500 ft.

A 4500ft circle would have a circumference of 14,136 ft (4500 x 3.1415).

My car has a wheelbase of 210 inches or 17.5ft.

In order to find the angle of the steering we take circumference divided by the wheelbase of the car to give the amount of the circle covered by the car and divide that into 360 to give the angle of the steering.

360 / (14,136/17.5) or 360/807 or 0.44 degrees........ not very much.

So if I get anywhere near 5 degrees it would be pretty much game over anyway and probably better to take a spin rather than get into a tank slapper.

Here’s another problem for the learned people of this site.

Take a worst case scenario, a spin & travelling sideways down the salt 200 mph.

Now if we take the maximum traction available as 0.6g, the cars track width is 32 inches, the height is 30 inches. I do not have a height yet for the centre of gravity but let’s say its 12 inches.

What would be the calculations to work out if it definitely would start to roll disregarding hitting a hole, crack, debris, blown tyre etc.

Lower COG, wider track, less speed or less traction would all make the chances of rolling less but it would good to have a calculation that could change variables to make sure there is a safety margin.