Wow, I didn't realize that I was lighting a brush fire!
Please consider the following points for sensible design goals on a cooling system for Bonneville:
The boiling point of water at Bonneville will be about 200F (at atmospheric pressure there). The system (unpressureized) proposed was a volume of water, so the temp of the reservoir at the end of a run should be less than 200F (probable target about 175-190F). That is why I listed the formula for a reservoir.
The flow of water across the heat generator (engine) should be in general much more than those little water puppy type units. The water flow carries away heat from the backside of the combustion chamber and the exhaust valves so that the chamber is less prone to encourage incipient detonation. That is why I listed the simple formula for water flow in gallons per minute (GPM). It is a pretty good rule of bruised thumb to use at least 10GPM/100Hp for heat dissipation.
It was well stated when it was said that there is much more to an accurate study of the thermodynamics of a water system, but I wanted to try and make it both understandable and usable without complex mathematics.
As to the question by the Cajun Kid: One would need a pump supplying about 106GPM with a reservoir of about 38 gallons (316lbs) to dissipate the heat from a 600Hp engine that would increase the temp from 100F to 180F in about 3minutes. That considers no cooling other than the mass of the water and with atmospheric pressure on the reservoir.
Things change appreciably when pressurizing the system and dissipation of some of the heat to atmosphere via forced or natural convection.
Hope that hasn't muddied up the cooling water issue too much.
It makes one appreciate how much heat a radiator actually dissipates in the cooling system and how nice the additional airflow across the radiator works at speed a;beit with some considerable drag involved.
Regards to All,
HB2